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What does this mean please?
Br2(g) + 2KI(aq) → 2KBr(aq) + I2(s)
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It's a chemical equation. Parts in brackets are the states of the matter ie, gas, aq-liquid etc. Left of arrow are the reactant that make up the products on the right. Will need to look up the chemicals. Why? I've seen that equation somewhere this week but my brains not awake yet.
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Bromine + Potassium Iodide = Potassium Bromide + Iodine
g = gas
aq = aqueous solution
s = solid
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I should have said it's a balanced chemical equation- there are the same amount of each element on each side of the equation.
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Bromine and Iodine are halogens and the equation is an example of a displacement reaction where the more reactive bromine displaces the iodine in the potassium iodide.
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What lourqhino says, Lol, can you do my homework too please? Salt, dissulfude and tother bridges refuse to stick in my brain
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step daughter is made up with answers so far cheers guys
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Originally Posted by
roving-eye
Br2(g) + 2KI(aq) → 2KBr(aq) + I2(s)
This is a net ionic equation or a single replacement/displacement reaction (replaces Br with Iodine) between Bromine gas and Potassium Iodide in aqueous or liquid form. The symbols in brackets are state symbols indicating solid, liquid or gas.
As others have said it is a redox equation which means reduction-oxidation as one substance is being reduced the other is being oxidised so:
Br2 has an overall ionic charge of zero as it is a compound in neutral state, but the Br in KBr has been reduced and has gained an electron:
K+ and Br-
and now has an ionic charge of -1, as K+ has an overall charge of +1.
Iodine in KI - is K+ and I- having an ionic charge of -1, this is changed to a charge of zero as I2 meaning it has been oxidised and has lost an electron.
OIL RIG - oxidation is loss, reduction is gain of an electron.
With redox equations you have two half equations that combine into a final equation. It is important that:
The atoms on both sides add up and
The charges balance on both sides so:
Br half equation:
Br2(g) + 2e- -> 2Br-
I half equation:
2I- -> I2 + 2e-
Combined:
Br2 + 2I- + 2K+-> 2Br- + I2 +K+ (notice without K+ atoms and charges still balance on both sides, K+ is a spectator ion)
or
Br2(g) + 2KI(aq) = 2KBr(aq) + I2(s)
With state symbols you can also see that the experiment would be performed by bubbling the Bromine gas through the KI and you would be left with an iodine precipitate which would usually be purple. Iodine sublimes so as soon as it is taken out of solution, it turns into a gas.
The equation is also an equilibrium equation meaning that the products are moving back and forth with the reactants, not simply -> we can use an = symbol.
It also concerns the halogen atoms, a more reactive halogen atom can replace a less active halogen atom from its salt in water. Fluorine is more reactive than Chlorine and so on:
F > Cl > Br > I so KBr can be replaced to KF in the same way, but not the other way around.
I can go on but I think this answers your question, hope it helped :-)
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It's an equation for the lubricant used on the Meniscus Fluffle Valve perfected by the Chinese Underwater Cavalry.
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